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What is a 4-digit number where the first number is one half the last number, the second number is doubled the first number, and the third number is one-fourth of the other three numbers combined?
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Let digits be A, B, C, D. A = D/2, B = 2A, C = (A+B+D)/4. Trying D=8 gives A=4, B=8, then C=(4+8+8)/4=5 → 4858 works.
